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Article

Asymptotic Justification of Models of Plates Containing Inside Hard Thin Inclusions

1
Lavrentyev Institute of Hydrodynamics of SB RAS, 630090 Novosibirsk, Russia
2
Department of Mathematics and Mechanics, Novosibirsk State University, 630090 Novosibirsk, Russia
Submission received: 1 October 2020 / Revised: 19 October 2020 / Accepted: 23 October 2020 / Published: 28 October 2020
(This article belongs to the Special Issue Advances in Multiscale and Multifield Solid Material Interfaces)

Abstract

:
An equilibrium problem of the Kirchhoff–Love plate containing a nonhomogeneous inclusion is considered. It is assumed that elastic properties of the inclusion depend on a small parameter characterizing the width of the inclusion ε as ε N with N < 1 . The passage to the limit as the parameter ε tends to zero is justified, and an asymptotic model of a plate containing a thin inhomogeneous hard inclusion is constructed. It is shown that there exists two types of thin inclusions: rigid inclusion ( N < 1 ) and elastic inclusion ( N = 1 ). The inhomogeneity disappears in the case of N ( 1 , 1 ) .

1. Introduction

An equilibrium problem of a Kirchhoff–Love plate containing a nonhomogeneous inclusion is considered. It is assumed that the elastic properties of the inclusion depend on a small parameter characterizing width of the inclusion ε as ε N with N < 1 . The problem is formulated as a variational one; namely, as a minimization problem of the energy functional over a set of admissible deflections in the Sobolev space H 2 . This implies that the deflections function is a solution of a boundary value problem for bi-harmonic operator (pure bending, see, e.g., [1,2,3,4]).
The aim of the present work is to justify passing to the limit as ε 0 . To do this, we apply a method that was originally introduced in [5,6] for problems of gluing plates. The method is based on variational properties of the solution to the corresponding minimization problem and allows for finding a limit problem for any N < 1 simultaneously. It is shown that there exist two types of hard inclusions in dependence of N: thin rigid inclusion ( N < 1 ) and thin elastic inclusion ( N = 1 ). In case N ( 1 , 1 ) , the influence of the inhomogeneity disappears in the limit. We get limit problems in a variational form, which is convenient, for example, for numerical analysis by the finite element method.
Let us give a short survey of works that are close to the present investigation. Note that there are not so many works devoted to study of models of thin inclusions in plates. We mention [7,8,9], in which thin elastic inclusions in pates were studied. Papers [10,11,12,13] are devoted investigations of thin rigid inclusions. We refer to [14,15,16,17,18,19,20,21] for asymptotic analyses for different models of bonded structures in Elasticity. We indicate also paper [22], where a geometry-dependent state problem for a heterogeneous medium with defects is investigated in framework of anti-plane elasticity.
Finally, we mention paper [23], where the mechanical behavior of an anisotropic nonhomogeneous linearly elastic three-layer plate with soft adhesive, including the inertia forces, was studied, and the various limiting models in the dependence of the size and the stiffness of the adhesive was derived. The problem under consideration in the present paper is different from the mentioned paper because we consider the hard inhomogeneity lying strictly inside the plate and derive limiting problem depending on the size and stiffness of the inclusion. Wherein, the plate size does not vary and remains constant.

2. Statement of Problem

Let us fix a small parameter ε ( 0 , 1 ) and consider an inhomogeneous rectangular plate Ω R 2 with a thin rectangular inclusion Ω i n c ε Ω of width 2 ε d , where d is diameter of Ω . Let us specify some notations:
Ω = ( a 1 , a 2 ) × ( b 1 , b 2 ) , a α , b α > 0 , α = 1 , 2 ,
Ω i n c ε = ( ε d , ε d ) × ( c 1 , c 2 ) , 0 < c α < b α , α = 1 , 2 ,
Ω ± = { ( y 1 , y 2 ) Ω | ± y 1 > 0 } ,
S = Ω Ω + ,
S i n c = S Ω i n c ε ,
Ω m a t ε = Ω \ Ω ¯ i n c ε , Ω ± ε = Ω m a t ε Ω ± ,
Note that, for all small enough ε > 0 a family of subdomains Ω i n c ε lies strictly inside Ω . Besides, let us define the following notations:
Ω m i d ε = { ( y 1 , y 2 ) Ω | ε d < y 1 < ε d , y 2 S } ,
S ± ε = { ( y 1 , y 2 ) Ω | y 1 = ± ε d , y 2 S } ,
We assume that S i n c is divided into three subsets S α S i n c , where each S α is an union of finite number of segments or empty set, α = 1 , 2 , 3 .
In our consideration, Ω is a composite plate, consisting of the elastic matrix Ω m a t ε and the inhomogeneous inclusion Ω i n c ε = α = 1 3 Ω α ε , where
Ω α ε = { ( y 1 , y 2 ) R 2 | ε d < y 1 < ε d , y 2 S α } , α = 1 , 2 , 3 .
Moreover, in the sequel, we will use the following notations:
Ω 0 ε = Ω m i d ε \ α = 1 3 Ω ¯ α ε ,
S 0 = S \ S ¯ i n c .
Denote, by E 0 , E α ε and k 0 , k α , Young’s modules and Poisson’s ratios of parts Ω m a t and Ω α ε of the composite plate Ω , respectively, α = 1 , 2 , 3 . The compound character of the structure is expressed by the fact that E 0 , k 0 , and k α are constants, while Young’s modulus E α ε depends on ε , as follows:
E α ε = ε N α E α in Ω α ε , α = 1 , 2 , 3 ,
where N 1 , N 2 , N 3 are real numbers, such that
N 1 < 1 , N 2 = 1 , N 3 ( 1 , 1 ) .
Parameters N 1 and N 2 correspond to hard inclusions in the plate Ω (see [6,24,25]). Moreover, put N 0 = 0 .
Denote, by w, deflections of the composite plate Ω . Then the bending moments are defined by formulae (see, e.g., [26,27])
m i j ( w ) = d i j k l ε w , k l , i , j = 1 , 2 , w , k l = 2 w y k y l ,
where the positive definite and symmetric tensor { d i j k l } is orthotropic with the following components:
d i i i i ε ( y ) = D ε ( y ) , d i i j j ε ( y ) = D ε ( y ) k ε ( y ) , d i j i j ε ( y ) = d i j j i ε ( y ) = D ε ( y ) ( 1 k ε ( y ) ) / 2 , i j , i , j = 1 , 2 ,
D ε ( y ) = D 0 in Ω m a t ε , ε N α D α in Ω α ε , α = 1 , 2 , 3 ,
D α = E α h 3 12 ( 1 k α 2 ) , α = 0 , 1 , 2 , 3 ,
k ε ( y ) = k 0 in Ω m a t ε , k α ε , in Ω α ε , α = 1 , 2 , 3 ,
h is a thickness of the plate Ω that is constant. Note paper [28], where it was shown non-standard behaviour in the asymptotic two-dimensional reduction from three-dimensional elasticity, when the thickness and size of inclusions depend on the same parameter.
The potential energy functional of the plate has the following representation (see [27]):
Π ( w ) = 1 2 Ω d i j k l ε w , k l w , i j d y Ω f w d y ,
where f L 2 ( Ω ) is a bulk force acting on the plate Ω . Subsequently, the equilibrium problem of nonhomogeneous plate clamped on the external boundary Ω can be formulated as the minimization problem: find a function w ε H 0 2 ( Ω ) such that
Π ( w ε ) = inf w H 0 2 ( Ω ) Π ( w ) .
Problem (2) is known to have a unique solution w ε (see, e.g., [26,29]), which satisfies the variational equality:
Ω d i j k l ε w ε , k l w , i j d y = Ω f w d y w H 0 2 ( Ω ) .
Moreover, the function w ε is a unique solution the following boundary value problem:
( d i j k l ε w ε , k l ) , i j = f in Ω ,
w ε = w ε ν = 0 on Ω ,
where ν is a unit normal vector Ω .

3. Decomposition of the Problem and Coordinate Transformations

In the sequel, we will have deal with the problem (3). Let us rewrite it in an equivalent form. For this, we introduce the following set:
K ε = { v = ( v , v + , v m ) H 2 ( Ω ε ) × H 2 ( Ω + ε ) × H 2 ( Ω m ε ) | v ± = v m , v ± , 1 = v m , 1 a.e. on S ± ε , v ± = v ± ν = 0 a.e. on Ω ± ε Ω } .
Taking into account the (1), problem (3) can be reformulated, as follows: find a triplet ( w ε , w ε + , w ε m ) K ε satisfying a variational equality
b ε ( w ε , v ) + b ε + ( w ε + , v + ) + b ε m ( w ε m , v m ) = = l ( v ) + l + ( v + ) + l m ( v m ) ( v , v + , v m ) K ε ,
where
b ε ± ( u , v ) = D 0 Ω ± ε ( u , 11 v , 11 + u , 22 v , 22 + k 0 ( u , 11 v , 22 + u , 22 v , 11 ) + 2 ( 1 k 0 ) u , 12 v , 12 ) d y ,
b ε m ( u , v ) = α = 0 3 D α ε Ω α ε ( u , 11 v , 11 + u , 22 v , 22 + k α ( u , 11 v , 22 + u , 22 v , 11 ) + 2 ( 1 k α ) u , 12 v , 12 ) d y .
l ε ± ( u ) = Ω ± ε f u d y , l ε m ( u ) = Ω m ε f u d y .
From the Calculus of Variations, it follows that problem (4) has a unique solution ( w ε , w ε + , ε m ) K ε for all ε > 0 small enough (see, e.g., [2,26]). Herewith, w ε ± and w ε m are restrictions of w ε on subdomains Ω ± ε and Ω m ε , respectively.
Next, we introduce coordinate transformations that map domains Ω ± ε and Ω m ε onto domains independent of ε . For this, we consider two convex domains ω 1 and ω 2 , such that
S ¯ ω 1 , ω ¯ 1 ω 2 , ω 2 { y 1 = a 1 } = , ω 2 { y 1 = a 2 } = ,
and a smooth cut-off function θ , such that
θ = 1 in ω ¯ 1 , 0 < θ < 1 in ω 2 , θ = 0 in R 2 \ ω ¯ 2 .
Let us introduce the following notations:
Ω m = { ( z 1 , z 2 ) R 2 | d < z 1 < d , z 2 S } ,
S ± = { ( z 1 , z 2 ) R 2 | z 1 = ± d , z 2 S } ,
Ω α = { ( z 1 , z 2 ) R 2 | d < z 1 < d , z 2 S α } , α = 0 , 1 , 2 , 3 ,
S α ± = { ( z 1 , z 2 ) R z 2 | z 1 = ± d , z 2 S α } , α = 0 , 1 , 2 , 3 .
and define coordinate transformations in the domains Ω ± and Ω m as follows:
y 1 = x 1 ± ε d θ ( x 1 , x 2 ) , y 2 = x 2 , ( x 1 , x 2 ) Ω ± , ( y 1 , y 2 ) Ω ± ε ,
y 1 = ε z 1 , y 2 = z 2 , ( z 1 , z 2 ) Ω m , ( y 1 , y 2 ) Ω m ε .
It is not difficult to show that for all sufficiently small coordinate transformations (5) and (6) map bijectively the domains Ω ± and Ω m onto Ω ± ε and Ω m ε , respectively, (see, e.g., [30,31]). Note that the subdomain Ω α ε is mapped into subdomains Ω α , α = 0 , 1 , 2 , 3 .
Denote, by Φ ε ± ( x ) and J ε ± , Jacobian matrices and Jacobians of transformations (5), respectively,
Φ ε ± ( x 1 , x 2 ) = 1 ± ε d θ , 1 ( x 1 , x 2 ) ± ε d θ , 2 ( x 1 , x 2 ) ) 0 1 ,
J ε ± ( x 1 , x 2 ) = det Φ ε ± ( x 1 , x 2 ) = 1 ± ε d θ , 1 ( x 1 , x 2 ) .
Coordinate transformations (5) and (6) establish one-to-one correspondences between spaces H 2 ( Ω ± ) , H 2 ( Ω m ) and H 2 ( Ω ± ε ) , H 2 ( Ω m ε ) , respectively. Moreover, the set K ε is transformed into a set K ε ,
K ε = { v = ( v , v + , v m ) H 2 , 0 ( Ω ) × H 2 , 0 ( Ω + ) × H 2 ( Ω m ) | v ± | S = v m | S ± , v ± , 1 | S = 1 ε v m , 1 | S ± } ,
where
H 2 , 0 ( Ω ± ) = { v ± H 2 ( Ω ± ) | v ± = v ± ν = 0 a.e. on Ω ± ε Ω } .
Hereinafter, we assume that, for any functions v ± ( x ) , x Ω ± , and v m ( z ) , z Ω m , equality v ± | S = v m | S ± means that
v ± ( 0 , x 2 ) = v m ( ± d , z 2 ) , x 2 = z 2 S .
Introduce the following notations:
w ± ε ( x 1 , x 2 ) = w ε ± ( x 1 ± ε d θ ( x 1 , x 2 ) , x 2 ) , ( x 1 , x 2 ) Ω ± ,
w m ε ( z 1 , z 2 ) = w ε m ( ε z 1 , z 2 ) , ( z 1 , z 2 ) Ω m .
Becase of the smoothness of coordinate transformations (5), we have asymptotic expansions for the transformations of the second-order derivatives for (5) (see, e.g., [30,31,32,33])
w ε ± , i j = w ± , i j ε + ε P i j ± ( ε , w ± ε ) ,
with
| P i j ± ( ε , w ± ε ) | C ( | w ± , k ε | + | w ± , k l ε | ) , i , j , k , l = 1 , 2 .
Besides, we have for (6)
w ε m , 11 ( y 1 , y 2 ) = w m , 11 ε ( z 1 , z 2 ) ε 2 , w ε m , 12 ( y 1 , y 2 ) = w m , 12 ε ( z 1 , z 2 ) ε , w ε m , 22 ( y 1 , y 2 ) = w m , 22 ε ( z 1 , z 2 ) .
After applying coordinate transformations (5) and (6) to (4), we get that the triplet ( w ε , w + ε , u w m ε ) K ε is a unique solution to the following variational equality:
b ε ( w ε , v ) + b + ε ( w + ε , v + ) + b m ε ( w m ε , v m ) = l ε ( v ) + l + ε ( v + ) + l m ε ( v m ) ( v , v + , v m ) K ε ,
where, taking into account (7) and (1),
b ± ε ( u , v ) = b ± ( u , v ) + r ± ( ε , u , v ) ,
b ± ( u , v ) = D 0 Ω ± ( u , 11 v , 11 + u , 22 v , 22 + k ± ( u , 11 v , 22 + u , 22 v , 11 ) + 2 ( 1 k ± ) u , 12 v , 12 ) d x ,
| r ± ( ε , u , v ) | c ± ( ε ) u H 2 ( Ω ± ) 2 + v H 2 ( Ω ± ) 2 , 0 c ± ( ε ) = o ( 1 ) as ε 0 ,
b m ε ( u , v ) = = D 0 Ω m u , 11 v , 11 ε 3 + ε u , 22 v , 22 + k m ε ( u , 11 v , 22 + v , 22 w , 11 ) + 2 ( 1 k m ) ε u , 12 v , 12 d z + + D 1 Ω m u , 11 v , 11 ε 3 N 1 + u , 22 v , 22 ε N 1 1 + k m ε 1 N 1 ( u , 11 v , 22 + v , 22 w , 11 ) + 2 ( 1 k m ) ε 1 N 1 u , 12 v , 12 d z + + D 2 Ω m u , 11 v , 11 ε 4 + u , 22 v , 22 + k m ε 2 ( u , 11 v , 22 + v , 22 w , 11 ) + 2 ( 1 k m ) ε 2 u , 12 v , 12 d z + + D 3 Ω m u , 11 v , 11 ε 3 N 3 + ε N 3 + 1 u , 22 v , 22 + k m ε 1 N 3 ( u , 11 v , 22 + v , 22 w , 11 ) + 2 ( 1 k m ) ε 1 N 3 u , 12 v , 12 d z ,
l ± ε ( v ) = Ω ± f ( x 1 ± d θ ( x 1 , x 2 ) , x 2 ) ( 1 ± d θ , 1 ( x 1 , x 2 ) v d x ,
l m ε ( v ) = ε Ω m f ( ε z 1 , z 2 ) v d z ,
| l ± ε ( v ) | C v L 2 ( Ω ± ) ,
| l m ε ( v ) | C ε v L 2 ( Ω m ) .

4. Limit Problem

To justify passing to the limit as ε 0 , we need some auxiliary lemma proved in [5,6].
Lemma 1
(Poincare-typé inequalities). For any triplet ( v , v + , v m ) K ε and ε ( 0 , 1 ) , the inequalities
v m L 2 ( Ω m ) 2 C v m , 11 L 2 ( Ω m ) 2 + v ± H 2 , 0 ( Ω ± ) 2 , v m , 1 L 2 ( Ω m ) 2 C v m , 11 L 2 ( Ω m ) 2 + ε 2 v ± , 1 L 2 ( S ) 2
hold, where a constant C > 0 does not depend on ( v , v + , v m ) and ε > 0 .
Our main result is the following theorem.
Theorem 1.
Let w ε = ( w ε , w + ε , w m ε ) be a solution to (8); let w 0 K 0 be a solution to the following variational equality:
b ( w 0 , w ) + 4 d ( 1 k 2 ) D m S 2 ( w 0 , 1 | S 2 ) z 2 ( w , 1 | S 2 ) z 2 d z 2 = l ( w ) w K 0 ,
where
K 0 = { w H 0 2 ( Ω ) | w = α x 2 + β a . e . o n S 1 , α , β R ; w , 1 H 1 ( S 2 ) } .
Denote, by w ± , a restriction of w to subdomain Ω ± and, moreover, put
w m ( z 1 , z 2 ) = w 0 ( z 1 , 0 ) f o r ( z 1 , z 2 ) Ω m .
Then, the following convergences
w ± ε w ± w e a k l y   i n H 2 ( Ω ± ) ,
w m ε w m w e a k l y   i n L 2 ( Ω m ) ,
take place as ε 0 .
Proof. 
Let us substitute ( w ε , w + ε , w m ε ) in (8) as a test function. Taking into account Lemma, (9)–(11), we obtain an estimate
w ε H 2 , 0 ( Ω ) 2 + w + ε H 2 , 0 ( Ω + ) 2 + + w m 0 , 11 ε ε 3 2 L 2 ( Ω 0 ) 2 + w m 0 , 12 ε ε 1 2 L 2 ( Ω 0 ) 2 + ε 1 2 w m 0 , 22 ε L 2 ( Ω 0 ) 2 + + w m 1 , 11 ε ε 3 N 1 2 L 2 ( Ω 1 ) 2 + w m 1 , 12 ε ε 1 N 1 2 L 2 ( Ω 1 ) 2 + w m 1 , 22 ε ε N 1 1 2 L 2 ( Ω 1 ) 2 + + w m 2 , 11 ε ε 2 L 2 ( Ω 2 ) 2 + w m 2 , 12 ε ε L 2 ( Ω 2 ) 2 + w m 2 , 22 ε L 2 ( Ω 2 ) 2 + + w m 3 , 11 ε ε 3 N 3 2 L 2 ( Ω 3 ) 2 + w m 3 , 12 ε ε 1 N 3 2 L 2 ( Ω 3 ) 2 + ε N 3 + 1 2 w m 3 , 22 ε L 2 ( Ω 3 ) 2 C
with a constant C independent of ε . Here, by w m α ε , denote a restriction of w ε to Ω α , α = 0 , 1 , 2 , 3 . Moreover, from (13), Lemma, and definition of the set K ε , we additionally have
w m ε L 2 ( Ω m ) C , w m , 1 ε L 2 ( Ω m ) C ε .
Estimates (13) and (14) entail the existence of functions w ± H 2 , 0 ( Ω ± ) , w m L 2 ( Ω m ) , p α , q α , r α L 2 ( Ω α ) , α = 0 , 1 , 2 , 3 , such that for some subsequence { ε n } n = 1 still denoted by ε , the following convergences:
w ± ε w ± weekly in H 2 ( Ω ± ) , w m ε w m weekly in L 2 ( Ω α ) , ε N α 3 2 w m , 11 ε p α weekly in L 2 ( Ω α ) , ε N α 1 2 w m , 12 ε q α weekly in L 2 ( Ω α ) , ε N α + 1 2 w m , 22 ε r α weekly in L 2 ( Ω α )
hold as ε 0 , with r 2 = w m , 22 . Moreover, from (13) and (14), it follows that
w m , 1 ε w m , 1 = 0 strongly in L 2 ( Ω m ) ,
w m , 11 ε w m , 11 = 0 strongly in L 2 ( Ω m ) ,
w m , 22 ε w m , 22 = 0 strongly in L 2 ( Ω 1 ) ,
and there exists u L 2 ( Ω m 2 ) such that
w ε ε u weekly in L 2 ( Ω 2 ) .
From definition of the set K ε , after passing to the limit as ε 0 , we obtain
w m | S ± = w ± | S .
Because w m , 1 = 0 in Ω m (see (16)), w m does not depend on z 2 . Therefore, taking into account (17), we conclude that there exists a function β ( z 2 ) L 2 ( Ω m ) such that
w m ( z 1 , z 2 ) = β ( z 2 ) , ( z 1 , z 2 ) Ω m .
Condition (18) means that the function w m is affine in the domain Ω m with respect to z 2 , i.e., there exists δ , γ R , such that
w m ( z 1 , z 2 ) = δ z 2 + γ in Ω 1 .
Because of (19), we have
w | S = w + | S .
Now, let us show that w ± satisfy the following equality:
w + , 1 = w , 1 on S .
Indeed, from the relation
d d w m , 11 ε ( z 1 , z 2 ) d z 1 = w m , 1 ε ( d , z 2 ) w m , 1 ε ( d , z 2 ) ,
it follows that
a b | w m , 1 ε ( d , z 2 ) w m , 1 ε ( d , z 2 ) | 2 d z 2 2 d w m , 11 ε L 2 ( Ω m ) 2 .
Due to estimate (13) and the equalities w m , 1 ε ( ± d , z 2 ) = ε w ± ε ( 0 , z 2 ) for z 2 ( a , b ) (see the definition of the set K ε ), we obtain
w + , 1 ε w , 1 ε L 2 ( S ) 2 d ε w m , 11 ε L 2 ( Ω m ) 0
as ε 0 . From (15) (the first line) and the compactness of trace operator, it follows
w ± , 1 ε w ± , 1 strongly in L 2 ( S )
as ε 0 , and (22) holds.
At last, using the same arguments as in [6], we can prove additionally that
w ± , 1 | S 2 H 1 ( S 2 )
and, moreover,
p 2 = k m w m , 22 in Ω 2 ,
q 2 = ( w , 1 | S 2 ) z 2 in Ω 2 ,
u = w , 1 | S 2 in Ω 2 .
Now, let us define a function
w 0 ( x ) = w ( x ) x Ω , w + ( x ) x Ω + .
Conditions (19)–(23) imply that the function w 0 belongs to the set K 0 .
In order to proceed with a problem defining the function w 0 , we take arbitrary function v C 2 ( Ω ) K 0 and define three functions v , v + , v m by
v = v | Ω , v + = v | Ω + ,
v m ( z 1 , z 2 ) = v ( 0 , z 2 ) , ( z 1 , z 2 ) Ω m .
Subsequently, for these functions, we consider a triplet ( v + ε ψ , v + + ε ψ + , v m + ε ψ m ) K ε , where ψ m ( z 1 , z 2 ) = v , 1 ( 0 , z 2 ) z 1 for ( z 1 , z 2 ) Ω m , and ψ ± H 2 , 0 ( Ω ± ) is arbitrary extensions of ψ m in domains Ω ± , such that
ψ ± | S = ψ m | S m ± , ψ ± , 1 = 0 on S ,
and substitute it in (8). Since v m , 11 = 0 and ψ m , 11 = 0 in Ω m , weak convergences in (15) and Formulas (23) allows for us to pass to the limit as ε 0 and obtain the following relation:
b ( w , v ) + b + ( w + , v + ) + 4 d ( 1 k 2 ) D 2 S 2 ( w , 1 | S 2 ) z 2 ( v , 1 | S 2 ) z 2 d z 2 = = l ( v ) + l + ( v + ) v C 2 ( Ω ) K 0 .
Taking into account (24) and the fact that C 2 ( Ω ) K 0 is dense in K 0 , we obtain (12). □
Assuming that the solution w 0 to variational problem (12) has additional regularity, by applying the generalized Green formula (see, e.g., [2,26]), we deduce differential equations and boundary conditions for the functions w 0 :
D 0 Δ 2 w 0 = f in Ω \ ( S ¯ 1 S ¯ 2 ) ,
w 0 = w 0 ν = 0 on Ω ,
w 0 = δ 0 x 2 + β 0 on S 1 , δ 0 , β 0 R ,
[ m 1 ( w 0 ) ] = 0 on S 1 ,
S 1 [ t 1 ( w 0 ) ] d x 2 = 0 , S 1 [ t 1 ( w 0 ) ] x 2 d x 2 = 0 ,
[ t 2 ( w 0 ) ] = 0 on S 2 ,
p = w 0 , 1 on S 2 ,
4 d D 2 ( 1 k 2 ) p , 22 = [ m 2 ( w 0 ) ] on S 2 ,
p , 2 = 0 at S 2 ,
where m α ( w 0 ) and t α ( w 0 ) are bending moments and transverse forces, respectively, defined by
m α ( w 0 ) = D α k α Δ w 0 + ( 1 k α ) 2 w 0 ν 2 ,
t α ( w 0 ) = D α ν Δ w 0 + ( 1 k α ) 2 w 0 τ 2 ,
ν = ( 1 , 0 ) and τ = ( 1 , 0 ) are an unit normal vector and an unit tangent vector, respectively, α = 1 , 2 .
The mechanical interpretation of boundary conditions can be found in [6], see also [10,34,35].

5. Concluding Remarks

We proposed a method of asymptotic derivation of plate models containing hard thin inclusions lying strictly inside the plate. The method is based on the variational properties of the solution of the equilibrium problem and allows for one to simultaneously construct all possible cases of hard thin inclusions. It is shown that there exist two type of thin inclusions in the Kirchhoff–Love plate, namely, the rigid inclusion S 1 for N < 1 and the elastic inclusion S 2 for N = 1 . The inhomogeneity disappears in the case of N ( 1 , 1 ) . The last means that we have no any peculiarity along the set S 3 .
In the conclusion, we note that the proposed method does not allow considering the case of the exponent N 1 simultaneously with the case of the exponent N < 1 , because, for the first case, we need to use other type of test functions (see [6]), which cannot be substituted in variational equality for the second case of the exponent.

Funding

The work is supported by the Russian Foundation for Basic Research (project 18-29-10007).

Conflicts of Interest

The authors have not conflict of interest.

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Rudoy, E. Asymptotic Justification of Models of Plates Containing Inside Hard Thin Inclusions. Technologies 2020, 8, 59. https://0-doi-org.brum.beds.ac.uk/10.3390/technologies8040059

AMA Style

Rudoy E. Asymptotic Justification of Models of Plates Containing Inside Hard Thin Inclusions. Technologies. 2020; 8(4):59. https://0-doi-org.brum.beds.ac.uk/10.3390/technologies8040059

Chicago/Turabian Style

Rudoy, Evgeny. 2020. "Asymptotic Justification of Models of Plates Containing Inside Hard Thin Inclusions" Technologies 8, no. 4: 59. https://0-doi-org.brum.beds.ac.uk/10.3390/technologies8040059

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